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Top K Frequent Elements

Question

Given a non-empty array of integers, return the k most frequent elements.

Example 1:
Input: nums = [1,1,1,2,2,3], k = 2
Output: [1,2]

Solution

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/*
@param: int[]
@return: int[]
Algorithm: 经典的Kth题目,利用heap来不断更新k elements。这里有个小技巧是可以用map.get来比较排序
*/
public int[] topKFrequent(int[] nums, int k) {
if (nums.length == 0 || k > nums.length) {
return new int[] {};
}

Map<Integer, Integer> map = new HashMap<>();
PriorityQueue<Integer> heap = new PriorityQueue<>((o1,o2) -> map.get(o1)-map.get(o2));

for (int i = 0; i < nums.length; i++) {
map.put(nums[i], map.getOrDefault(nums[i], 0)+1);
}

for (int n : map.keySet()) {
heap.offer(n);
if (heap.size() > k) {
heap.poll();
}
}

int[] res = new int[heap.size()];
int i = 0;
for (int n : heap) {
res[i++] = n;
}
return res;
}